How Much Weight Can a DC Motor Carry?
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The weight a DC motor can carry depends on three factors: 它的 扭矩输出, 这 radius of the pulley or lever arm, 和 gear reduction ratio. The fundamental formula is mass = torque / (radius × g), where g is gravitational acceleration (9.81 米/秒²). A small DC motor rated at a few watts may lift only a few kilograms, while a gear motor rated at several hundred watts can lift hundreds of kilograms. 例如, 一个电机 173.6 N-cm rated torque using a 2 cm radius pulley can lift approximately 8.85 kg directly — and with a 10:1 gearbox at 90% 效率, that capacity increases to about 79.7 千克. 每 国际电工委员会 60034-1 和 一氧化氮镁 1, motors must be derated when operated above their continuous duty rating, so a safety factor of 1.5–2.0× should always be applied to weight capacity calculations.

What Determines DC Motor Weight Capacity?
DC motor weight capacity is not a single specification — it is the result of the interaction between the motor’s 扭矩输出, the mechanical transmission system, and the thermal limits of the motor. Understanding these relationships requires defining several key terms:
- 扭矩 (时间) — The rotational force produced by the motor, measured in N·m (牛顿米) or kg·cm. Torque is the primary determinant of how much weight a motor can move.
- 堵转扭矩 (时间摊位) — The maximum torque the motor produces when the shaft is prevented from rotating. Operating at stall torque for more than a few seconds will destroy most motors due to excessive current and heat.
- Rated (nominal) 扭矩 (时间额定) — The torque the motor can deliver continuously without exceeding its insulation class temperature limit. This is the value used for sustained weight-lifting calculations.
- Pulley radius (r) — The distance from the motor shaft center to the point where the lifting force is applied. A smaller radius allows the motor to lift more weight but at a slower linear speed.
- 齿轮比 (一世) — The ratio by which a 变速箱 reduces speed and multiplies torque. 一个 10:1 gear ratio multiplies torque by approximately 9× (占 90% 变速箱效率).
- 工作周期 — Per NEMA MG 1 部分 10 和国际电工委员会 60034-1, the duty cycle (S1 continuous, S2 short-time, S3 intermittent) defines how long the motor can sustain a given load. Weight capacity must be calculated against the intended duty cycle.
The relationship between these parameters is governed by the torque equilibrium equation: the motor’s output torque must exceed the torque created by the load (mass × gravity × radius) for lifting to occur.
How DC Motors Generate Torque: 一步一步
To understand weight capacity, it helps to trace how a DC motor converts electrical input into the mechanical torque that ultimately lifts a load:
- 磁场建立 — In a 有刷直流电机, 永磁体 (or field windings) in the stator create a stationary magnetic field. 在一个 无刷直流电机, the controller sequentially energizes stator phases to create a rotating field.
- Armature current flow — When voltage is applied, current flows through the armature windings (拉丝的) or stator phases (无刷). The magnitude of this current directly determines torque: T=Kt × Φ × 我一个, 其中 Kt 是扭矩常数, Φ is magnetic flux, 和我一个 is armature current.
- Lorentz force and rotation — Current-carrying conductors in the magnetic field experience a force (F = 胆汁) perpendicular to both field and current. This force creates torque on the rotor, 使其旋转.
- Back-EMF and equilibrium — 当转子旋转时, 它产生反电动势 (反电动势) 与速度成正比. At steady state, the motor reaches an equilibrium where the net current produces exactly enough torque to balance the load.
- Torque transmission to load — The motor shaft torque is transmitted through a coupling, 滑轮, 齿轮, or leadscrew to the load. The mechanical advantage of this transmission system determines the final lifting force.
The key insight for weight capacity is step 5: the motor’s shaft torque is only the starting point. The transmission system — gears, 滑轮, levers — determines how that torque translates into lifting force. This is why a small motor with the right gearbox can lift surprisingly heavy loads.
DC Motor Types: Weight Capacity Comparison Table
| 电机类型 | Typical Torque Range | Typical Weight Capacity* | 最适合 | Limitation |
|---|---|---|---|---|
| Coreless DC motor (例如, Faulhaber 1506SR) | 0.4–0.6 mNm (摊位) | < 1 gram (直接驱动) | Precision instruments, 微型机器人 | Extremely low torque; requires micro-gearbox |
| Small brushed DC motor (例如, 福尔哈伯 0816) | 1.0–1.15 mNm (摊位) | ~10–15 grams (直接驱动) | 玩具, small actuators, camera drives | 电刷磨损; limited continuous torque |
| 无刷直流伺服电机 (例如, 福尔哈伯 2057 BA) | 309 米米 (摊位); 13.7 米米 (额定) | ~1.5 kg (direct); ~15 kg (和 10:1 变速箱) | 机器人学, 医疗器械, 自动化 | 需要控制器; 成本较高 |
| High-performance DC motor (例如, maxon RE 40) | 1,020 米米 (摊位); 189 米米 (额定) | ~5.2 kg (direct); ~47 kg (和 10:1 变速箱) | 机器人学, 工业自动化, climbing robots | Brush maintenance; 48V supply required |
| Industrial gear motor (例如, 12V 390W with 800:1) | 560 牛顿·米 (输出, 带变速箱) | ~800 kg (with appropriate pulley) | Door operators, 提升机, 盖茨, 电梯 | 低速; large physical size |
*Weight capacity values assume vertical lifting with a 2 cm radius pulley at motor rated torque (not stall torque), 与一个 0.7 安全系数. Actual capacity depends on gear ratio, pulley diameter, 占空比, 和环境温度.
工程数据: 扭矩公式, 效率, and Temperature Limits
Core Torque and Weight Formulas
The following equations govern the relationship between motor torque and lifting capacity. These are derived from classical mechanics and are consistent with the torque calculation methodologies described in the maxon DC motor technical handbook and Faulhaber product documentation:
1. Torque required to lift a mass (vertical lifting):
t = (m × g) × r
where τ = torque (牛顿·米), m = mass (千克), 克= 9.81 米/秒², r = pulley radius (米)
2. Maximum weight a motor can lift:
米最大限度 = T摊位 / (r × g)
Use rated torque with safety factor for continuous operation
3. Gearbox output torque:
时间出去 = T马达 × i × n
where i = gear ratio, η = 变速箱效率 (typically 0.85–0.95 per stage)
4. Motor power from torque and speed:
P = T × ω = T × (2π × n / 60)
Or: 时间 (牛顿·米) = 9550 × P (千瓦) / n (转速)
5. DC motor torque from current:
T=Kt × 我一个
其中 Kt = 扭矩常数 (牛·米/A), 我一个 = armature current (一个)
工作示例: 12V 100RPM 173.6 N-cm DC Motor
The existing Greensky Power article references a 12V 100RPM DC motor with 173.6 N-cm rated torque. Here is the complete weight capacity calculation:
| 范围 | 价值 | 计算 |
|---|---|---|
| 额定扭矩 | 173.6 N-cm = 1.736 牛顿·米 | 给定 |
| Pulley radius | 2 cm = 0.02 米 | Selected (common size) |
| Theoretical max weight | 8.85 千克 | 1.736 / (0.02 × 9.81) |
| 和 70% 安全系数 | 6.2 千克 | 8.85 × 0.7 |
| 和 10:1 变速箱 (90% eff.) | 79.7 千克 | 1.736 × 10 × 0.9 / (0.02 × 9.81) |
| 和 10:1 变速箱 + 70% 安全 | 55.8 千克 | 79.7 × 0.7 |
This demonstrates why the gear ratio is the single most powerful tool for increasing weight capacity: 一个 10:1 gearbox increased lifting capacity from 8.85 公斤至 79.7 kg — a 9× improvement. For more on gearbox selection, 看看我们的 变速箱选型指南.
Efficiency and Power Loss Data
Motor efficiency directly affects weight capacity because wasted energy becomes heat, which limits the continuous torque output. Per a 2026 IEEE Access study on PMDC motor optimization by Esenboğa, efficiency improvements from 74.1% 至 84.6% increased torque output from 3.93 N·m to 4.93 N·m — a 25% improvement through magnet geometry optimization alone.
| 电机类型 | 最大效率 | Primary Loss Source | 参考 |
|---|---|---|---|
| 福尔哈伯 0816 (coreless, 拉丝的) | 69% | Precious metal brush friction | Faulhaber datasheet |
| maxon RE 40 (coreless, 拉丝的) | 89% | Graphite brush + 绕线电阻 | maxon technical handbook |
| 福尔哈伯 2057 BA (无刷直流) | 90% | 绕线电阻 + 铁损 | Faulhaber datasheet |
| Typical PMDC (iron core, 拉丝的) | 74–85% | 铁损 + 刷子摩擦力 + I²R | IEEE Access (Esenboğa, 2026) |
温度限制 (国际电工委员会 60034-1 Insulation Classes)
When a DC motor lifts heavy loads, the armature current increases, generating heat through I²R losses. If the winding temperature exceeds the insulation class limit, the motor will fail. 根据 IEC 60034-1:
| 绝缘级别 | 最高绕组温度 | Allowed Temp Rise (40°C 环境温度) | Example Motor |
|---|---|---|---|
| B类 | 130℃ | 80℃ | Standard industrial PMDC |
| F级 | 155℃ | 100℃ | maxon RE 40 (155°C limit); most industrial motors |
| H级 | 180℃ | 125℃ | 重负 / high-temp motors |
| Special (福尔哈伯 2057 BA) | 140℃ | 100℃ | BLDC with stainless steel housing |
At rated torque, a motor typically reaches thermal equilibrium at 60–80% of its insulation class limit. When lifting heavy loads near stall torque, the temperature can exceed the limit within seconds. 热传感器 (PTC or NTC thermistors embedded in the windings) or current limiting in the 电机控制器 are essential for heavy-load applications. 看看我们的 motor testing standards guide for thermal test procedures.
Duty Cycle Ratings (一氧化氮镁 1 / 国际电工委员会 60034-1)
Weight capacity is meaningless without specifying the duty cycle. A motor can lift a much heavier load for 5 秒 (S2 short-time duty) than it can lift continuously (S1 continuous duty):
- S1 (连续工作) — Motor runs at constant load long enough to reach thermal equilibrium. Use rated torque for capacity calculations.
- S2 (短时值班) — Motor runs at constant load for a specified time (10, 30, 60 分钟), then rests. Can handle 1.3–1.5× rated torque during the active period.
- S3 (间歇性周期性工作) — Alternating periods of load and rest (例如, 60% 占空比). Capacity depends on the on/off ratio; typically allows 1.1–1.3× rated torque.
- S4/S5 (Intermittent with starting/braking) — Frequent starts and stops add thermal stress from high inrush current. Derate capacity by 10–20%.
Best Applications for DC Motors in Weight Lifting
1. Electric Hoists and Winches
12V and 24V DC gear motors are the standard for portable electric hoists, ATV winches, and boat trailer winches. A typical 12V 2000W winch motor with a 300:1 planetary gearbox can pull up to 4,000 千克 (8,800 磅) on a single line. The high gear ratio trades speed for massive torque multiplication. For our 有刷直流电机 platform, common hoist applications use motors rated at 200–500W with 100:1 至 500:1 变速箱.
2. 机器人与自动化
In robotic arm joints, 直流电机 (particularly BLDC servos) lift payloads through lever arms. The torque requirement is calculated as T = (payload_mass × g × arm_length) / gear_ratio. 对于一个 5 kg payload on a 0.3 m arm with a 100:1 harmonic drive at 85% 效率, the motor must deliver at least 0.173 N·m — well within the range of a Faulhaber 2057 BA BLDC motor (13.7 mNm rated, 309 mNm stall). 看看我们的 robotics motor guide for servo-grade BLDC specifications.
3. Electric Vehicles and Material Handling
DC motors power electric forklifts, 托盘搬运车, 和 electric forklift motors that carry loads of 1,000–5,000 kg. These applications use 24V or 48V series-wound DC motors rated at 1–10 kW, paired with differential gearboxes. The high starting torque of DC motors (up to 400–500% of rated torque) is essential for accelerating heavy loads from standstill. For e-bike and scooter applications, 我们的 电动自行车电机控制器指南 covers BLDC drive systems.
4. Door and Gate Operators
Sliding gate operators and automatic door systems use 12V or 24V DC gear motors to move doors weighing 200–800 kg. The Mingniao DC800K motor, 例如, is rated at 24V 390W with an 800 kg door weight capacity — achieved through a high-ratio gearbox that delivers 560 N·m output torque at just 3 转速. 看看我们的 gear motor with speed control page for similar configurations.
5. Medical and Laboratory Equipment
Patient lifts, adjustable hospital beds, and laboratory actuators use precision DC gear motors to lift loads of 50–200 kg with smooth, 安静运行. Brushless DC motors are preferred for their low maintenance and precise speed control. Faulhaber BLDC motors with integrated encoders are commonly specified for FDA-compliant medical devices. 看看我们的 micro DC gear motor guide for low-speed, high-torque configurations.
Step-by-Step Motor Selection for Weight Lifting
Follow this six-step process to calculate the required DC motor specifications for your weight-lifting application:
- Define the load and motion. Determine the mass to be lifted (千克), the lifting direction (垂直的, inclined, or horizontal), the required linear speed (多发性硬化症), and the duty cycle (连续的, 间歇性的, short-time). Vertical lifting requires overcoming gravity (F = m × g); horizontal movement only requires overcoming friction (F = m × g × μ, where μ is the friction coefficient, typically 0.05–0.3 for wheels on flat surfaces).
- Calculate the required output torque. Using the pulley or drum radius: 时间加载 = F × r = (m × g) × r. 对于一个 50 kg load on a 3 cm radius drum: 时间加载 = 50 × 9.81 × 0.03 = 14.7 牛顿·米. Add acceleration torque if the load must be accelerated: 时间加速 = J × a (moment of inertia × angular acceleration).
- Select the gear ratio. Choose a gear ratio that reduces the motor’s rated torque to exceed the load torque with a safety margin: i ≥ T加载 / (时间motor_rated × η × SF), where η is gearbox efficiency and SF is the safety factor (1.5–2.0). For our 14.7 N·m load with a motor rated at 1 牛顿·米, 90% 变速箱效率, 和 1.5 安全系数: i ≥ 14.7 / (1 × 0.9 × 1.5) = 10.9 → select a 12:1 变速箱. 看看我们的 变速箱选型指南 for ratio and type selection.
- Verify the motor speed. The output speed after gearing must meet the required lifting speed: n出去 = n马达 / 一世. Linear speed = n出去 × 2π × r / 60. If the motor runs at 3,000 转速与 12:1 gearbox and 3 cm drum, the lifting speed is (3000/12) × 2π × 0.03 / 60 = 0.785 多发性硬化症. Adjust the gear ratio or motor speed if this is too fast or slow.
- Check thermal limits. Calculate the motor’s continuous power requirement: P = T马达 × Ø马达. Ensure the motor’s rated power exceeds this value. Check that the expected temperature rise (based on I²R losses and the motor’s thermal resistance, typically listed in datasheets as Rth1 和Rth2) stays within the insulation class limit. For the Faulhaber 2057 BA, the winding-to-ambient thermal resistance is 1.1 K/W — a 1.0 A current through 0.427 Ω resistance generates 0.427 W of heat, raising the winding temperature by 0.47°C above ambient, well within the 140°C limit.
- Specify protection devices. Install a current-limiting 电机控制器 that cuts power when armature current exceeds 1.5× rated current. Add a thermal cutoff or PTC thermistor in the windings. For battery-powered applications, include a fuse rated at 1.25× the maximum operating current. For heavy loads, 考虑一个 定制电机设计 with integrated thermal protection.
Common Engineering Mistakes When Calculating DC Motor Weight Capacity
- Using stall torque instead of rated torque. Stall torque represents the absolute maximum at zero speed — operating a motor at stall for more than a few seconds will cause thermal failure. Always calculate continuous weight capacity using rated torque, and reserve stall torque only for momentary peak loads (例如, breakaway torque). The maxon RE 40 has a stall torque of 1,020 mNm but a rated torque of only 189 mNm — using stall torque overstates capacity by 5.4×.
- Ignoring gearbox efficiency losses. Each gear stage loses 5–15% of torque to friction. A three-stage planetary gearbox with 90% per-stage efficiency transmits only 0.9³ = 72.9% of input torque. Engineers who calculate output torque as T马达 × i without the efficiency factor will overestimate capacity by 27%.
- Neglecting acceleration torque. A motor must overcome not only the static load (gravity) but also the inertial force needed to accelerate the mass from rest: F加速 =米×a. 对于一个 50 kg load accelerated at 2 米/秒², the additional force is 100 N — equivalent to adding 10.2 kg to the static load. This is often overlooked in applications like elevators and robotic arms.
- Using the wrong pulley radius. The lifting capacity is inversely proportional to pulley radius. Doubling the pulley radius halves the lifting capacity but doubles the linear speed. Engineers sometimes select a large pulley for speed, then discover the motor cannot lift the intended load. Always verify capacity after finalizing the mechanical design.
- Not derating for ambient temperature and altitude. 根据 IEC 60034-1, 当环境温度超过 40°C 或海拔超过 1,000 米. At 50°C ambient, the allowable temperature rise decreases by 10°C, reducing continuous torque capacity by approximately 8–12%. 在 2,000 米海拔, derate by an additional 10% due to reduced air cooling.
- Overlooking duty cycle in motor selection. A motor rated for S1 (连续的) duty at 100W cannot deliver 200W for 30 minutes in S2 duty without exceeding thermal limits — the relationship is not linear. Always check the manufacturer’s duty cycle derating curve, and select a motor with the correct efficiency rating for the intended operating profile.
故障排除表: DC Motor Weight Capacity Problems
| 问题 | 可能的原因 | 解决方案 |
|---|---|---|
| Motor stalls when lifting the target weight | Load torque exceeds motor stall torque; insufficient gear ratio | Increase gear ratio; use a motor with higher torque constant (Kt); reduce pulley radius |
| Motor lifts load but overheats within minutes | Operating above rated torque; 冷却不足; 错误的占空比 | Check current vs. 额定电流; add forced air cooling; switch to intermittent duty (S3); select a larger motor |
| Motor lifts load but speed is too slow | Excessive gear reduction; voltage too low; load near rated torque | Reduce gear ratio (verify torque margin); increase supply voltage within rated limits; use a higher-power motor |
| Motor cannot start under load | Starting torque insufficient; static friction higher than expected; voltage sag under load | Add a soft-start controller; increase gear ratio; use a motor with higher starting torque (series-wound DC) |
| Motor lifts load initially, then loses capacity over time | Thermal derating as winding heats up; 电刷磨损; battery voltage sag | Add thermal monitoring; check brush length; verify battery capacity and voltage under load |
| Gearbox fails or strips under load | Output torque exceeds gearbox rating; 冲击载荷; 错位 | Select gearbox with higher torque rating; add torque limiter or slip clutch; check alignment per NEMA MG 1 公差 |
| Load drops when power is removed | No holding brake; gearbox backdrivable | Install electromagnetic brake; use worm gearbox (self-locking at ratios > 20:1); add mechanical ratchet |
| Inconsistent lifting capacity | Voltage fluctuations; intermittent brush contact; gearbox lubrication breakdown | Use regulated power supply; inspect brush/commutator; replace gearbox lubricant per maintenance schedule |
常问问题: DC Motor Weight Capacity
1. How much weight can a DC motor carry?
The weight a DC motor can carry depends on its torque rating, the radius of the pulley or lever arm, and the gear ratio. The formula is mass = torque / (radius × 9.81). 例如, 一个电机 173.6 N-cm torque using a 2 cm radius pulley can lift approximately 8.85 千克. 与一个 10:1 gearbox at 90% 效率, the lifting capacity increases to about 79.7 千克. Always apply a safety factor of 1.5–2.0× for continuous operation.
2. How do you calculate the lifting capacity of a DC motor?
使用公式: 米最大限度 = T摊位 / (r × g). 第一的, convert stall torque to N·m. Then divide by the product of pulley radius (in meters) and gravitational acceleration (9.81 米/秒²). Apply a safety factor of 0.5–0.7 to account for efficiency losses, 摩擦, and acceleration requirements. For geared motors, multiply the motor torque by the gear ratio and efficiency before calculating: 时间出去 = T马达 × i × n. 看看我们的 electric motor basics guide for more calculation examples.
3. How does gear ratio affect the weight a DC motor can carry?
A gearbox multiplies torque while reducing speed. The output torque equals motor torque multiplied by the gear ratio and efficiency: 时间出去 = T马达 × i × n. 例如, 一个 10:1 gearbox with 90% efficiency multiplies torque by 9. 某电机生产 2 N·m torque can deliver 18 N·m at the gearbox output, increasing lifting capacity by 9×. 然而, the output speed decreases by the same ratio. 看看我们的 direct drive vs gear motor comparison for trade-off analysis.
4. What is the difference between stall torque and rated torque for weight lifting?
Stall torque is the maximum torque a motor produces when the shaft is held at zero speed — it should never be used as a continuous operating point. Rated (nominal) torque is the torque the motor can deliver continuously without exceeding its thermal limit per IEC 60034-1. For weight lifting applications, always size the motor based on rated torque, not stall torque, and apply a safety factor of 1.5–2.0×. The maxon RE 40, 例如, has a stall torque of 1,020 mNm but a rated torque of only 189 米米.
5. Can a 12V DC motor lift heavy loads?
是的. The voltage rating (12五) does not directly determine lifting capacity — torque does. A 12V DC motor with high torque output, combined with a suitable gearbox, can lift hundreds of kilograms. 例如, a 12V motor rated at 390W with an 800:1 gearbox can lift up to 800 千克, as demonstrated in door operator applications. The key is matching the motor’s torque constant (Kt) and the gear ratio to the load requirement. 看看我们的 12V BLDC 电机控制器 page for 12V system configurations.
6. What temperature limits apply to DC motors carrying heavy loads?
根据 IEC 60034-1, motor insulation classes define maximum winding temperatures: B级允许130°C, F 级允许 155°C, H级允许180°C. When carrying heavy loads, motor temperature rises due to copper losses (I²R). Continuous operation at or near stall torque will rapidly exceed thermal limits. The Faulhaber 2057 BA specifies a maximum winding temperature of 140°C with a thermal resistance of 1.1 千瓦/瓦 (winding to housing). Thermal protection (PTC thermistors) or current limiting in the motor controller is essential for heavy-load applications.
Why Choose Greensky Power for Your DC Motor Solutions?
Calculating weight capacity is only the first step — sourcing a motor that reliably delivers the required torque under real-world conditions is where Greensky Power adds value. 自从 2011, we have manufactured 直流电机 for B2B customers in 50+ 国家, with a product portfolio spanning 有刷直流电机, 无刷直流电机, 变速箱, 和 电机控制器.
Our engineering capabilities for weight-lifting applications include:
- Integrated motor + 变速箱 + 控制器解决方案 — Rather than sourcing each component separately, we design the motor, 变速箱, and controller as a system, ensuring the torque, 速度, and thermal characteristics are matched for your specific load requirement. 看看我们的 brushed vs brushless DC motor guide to select the right motor type.
- Custom torque optimization — 我们的 R&D队的 8 博士级工程师提供 定制电机设计 with optimized torque constants (Kt), winding configurations, and magnetic circuit designs. 我们再投资 10% 年收入投入 R&D and use ANSYS Maxwell FEA simulation for electromagnetic design.
- 100% 负载测试 — 每个电机都会经历 individual dynamometer testing to verify torque output, 效率, and thermal performance under load. We test to IEC 60034-2 efficiency measurement standards and NEMA MG 1 performance specifications.
- Thermal protection integration — For heavy-load applications, we embed PTC thermistors in the windings and configure current limiting in the controller to prevent thermal overload. Our motors are certified to ISO, 行政长官, and energy efficiency standards.
- Regional engineering support — 针对北美和欧洲客户, our subsidiary United Motion Inc. provides local technical consultation, 样品测试, and after-sales warranty support. 联系我们的工程团队 to discuss your weight-lifting application requirements.
参考
- 国际电工委员会. 国际电工委员会 60034-1:2022 — 旋转电机 — 零件 1: 评级和性能. 可用于: https://webstore.iec.ch/publication/61474
- 全国电气制造商协会. 一氧化氮镁 1-2021 — 电动机和发电机 (部分 10: 工作周期; 部分 12: Tests and Performance). 可用于: https://www.nema.org/standards/view/Motors-and-Generators
- 马克森电机股份公司. 直流电机: 空心杯绕组永磁直流电机 — 技术手册. 可用于: https://www.maxonmotor.com/medias/sys_master/root/8803450421278/maxonDCmotor-Handouts.pdf
- 福尔哈伯. Brushless DC-Servomotors 2057…BA Series — Technical Datasheet. 可用于: https://eshop.faulhaber.com/cn/2057-…-BA/Serie-2057-…-BA
- 福尔哈伯. Brushless DC-Servomotors 1660S024BHT Series — Product Page. 可用于: https://www.faulhaber.com/en/products/series/1660bht
- 福尔哈伯. Flat DC-Micromotors 1506SR Series — Technical Datasheet. 可用于: https://www.faulhaber.com/en/products/series/1506sr
- 精密微驱动器. “Torque Calculations for Gearmotor Applications.” Technical Application Note. 可用于: https://www.precisionmicrodrives.com/content/torque-calculations-for-gearmotor-applications
- INEED Motors. “How To Select The Right Motor And Reducer For Your Application.” 工程指南. 可用于: https://ineedmicromotors.com/select-right-motor-and-reducer-for-your-application-guide/
- Handson Technology. Motor/Torque Equations and Lifting Calculation Examples — Application Note. 可用于: https://www.handsontec.com/dataspecs/motor_fan/GA12-N20.pdf
- Esenboğa, 乙. (2026). “Parametric Sensitivity-Based Optimization of Additively Manufactured Permanent Magnets for Enhanced PMDC Motor Performance.” IEEE Access, 卷. 14, PP. 45179–45190. DOI: 10.1109/ACCESS.2026.3676935
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